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Finding stress at an angle for a rotating part

Sam_92
4-Participant

Finding stress at an angle for a rotating part

Hi,

 

We need to find the stress when the part is twisted at an angle. It's shown in the capture-1 below that a motor powers the pocket at one end, while the other end has a stopper. load (capture 2) & constrains (capture 3), kindly advise me on how to calculate the stress values at various angles? 

Plastic is the material that is used & currently I am using Creo 7

 

Thanks

olivierlp_0-1719234777162.png

 

olivierlp_1-1719234788634.png

 

olivierlp_2-1719234797278.png

 

1 ACCEPTED SOLUTION

Accepted Solutions

14 REPLIES 14

please send a step-file

Sam_92
4-Participant
(To:skunks)

Please find attached file.

 

Thanks

attached file ZIP

example

2024-06-24_example.png

Sam_92
4-Participant
(To:skunks)

Hi Skunks,

 

Thanks for the quick response and solution.

 

in-addition,

Could you please help me? How can we specify angles, say 20 degrees, such that twisting stops at that point and we have to determine the stresses?

Plus, after applying 1NM, is it possible to measure the amount of twist(angle)?

 

Thanks.

Angle 20 degrees?
Oh... This is an extremely non-linear problem, plasticity, large deformations...

very complex.

I'm building an example, OK?

Sam_92
4-Participant
(To:skunks)

yes, please

Sam_92
4-Participant
(To:skunks)

The part's primary purpose is to rotate 20 degrees past a stopper on one side so that we can measure the deformation and determine the stresses at that 20-degree angle.

 

Thanks.

Enclosed is a more elegant version 😁

 

(non-linear later)

V2:

2024-06-25_V2.png

V3 for (exactly) angle 20" (measure "angle"

2024-06-25_angle.png

V4:

2024-06-25_20deg.png

 

SweetPeasHub_0-1719433729184.png

Having shell elements does not allow Large Displacement. We just need a simple spring with low stiffness (1D element)

SweetPeasHub_1-1719434322202.png

 

Thank you!
The user also has the problem of plasticization in the notches.

This is still too demanding for a beginner 😂

A linear calculation is therefore more practicable.

 

PS: We often use a compressive load as a force pair; in the event of large deformations, this load is tracked.

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