5log_{12}(2)
Do not become concerned, that 5 in front is just multiplication. It may be more clearly written:
5�log_{12}(2)
OR, with a logarithm property
log_{12}(2^{5})
Neither of these should pose much problem for entry into StudyWorks.
The Base 12, on the other hand, is a bit trickier, since StudyWorks does not have an arbitrary base placeholder on a logarithm function. All is not lost, however, knowing this principle:
log_{b}(a) = log_{c}(a) / log_{c}(b)
Where 'c' is anything valid (For example, -1 might be a bad choice and zero (0) would be a very bad choice.) c=10 is very popular before calculus. c=e is very popular after calculus.
Using c=10, then: (Recall log_{with no base written}() is assumed to be base 10)
log_{12}(2^{5}) = log(2^{5}) / log(12)
5�log_{12}(2) = 5�log(2) / log(12)
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