Hello
I have the next formulae of power but I think there is an mistake, Please somebody help me
Pot=(PxQ/360)/1.358
P pressure in bar=225 bar
Q flow in l/min=78 l/min
Pot=( (78*225)/360)/1.358=35,8kW
Thanks
Hi,
The equation is an empirical one in that it is not unit consistent.
So you need to strip the units from each term of the equation.
Do this by dividing.
Then you need to apply the units of the equation.
Terry,
The equation is unit consistent:
We need to look harder at his sheet.
Hi
where did you get the following information?
Pot=(PxQ/360)/1.358
P pressure in bar=225 bar
Q flow in l/min=78 l/min
Hi
This Iis in a hydraulic manual.
It's usually in hydraulic power calculations
JM
@JM_3218201 wrote:
Hi
This Iis in a hydraulic manual.
It's usually in hydraulic power calculations
JM
Hi,
how do you know that the result of Pot=( (78*225)/360)/1.358 should be 35.8 kW ?
(Fred_Kohlhepp)
I am just uploading my exercise ... verification of the formula
This is a very nice demonstration that Mathcad's unit conversion works:
Well done,
The question is why does the formula originally posted result in a different answer?
Hi
I have revised some hydraulic books an I think you have proposed are OK
I think the problem are the units
Pot=(PXQ)/(612xµ)
P=bar or kg/cm2
Q=l/min
Pot=kW
Thanks
The formula has values for unit conversion and also efficiency (I believe).
See attached