Integration in MathCad

[ptc-4493261]

Hi All,

I am trying to set up the following definite Integral in MathCad as a function of wt, not just t, how would I do that.

eg (1/2pi) Int 0 to 3 sin(wt-0.361) dwt.

Thanks in advance.

Vijay

[ValeryOchkov]

[ptc-4493261]

Thanks Valery,

I have MathCad 15, also wt = 2*pi*60.*t

Will this work in MathCad 15.

Vijay

[ValeryOchkov]

Vijay Khatri wrote:

Thanks Valery,

I Will this work in MathCad 15.

Vijay

Try pls

[Werner_E]

Vijay Khatri wrote:

Thanks Valery,

I have MathCad 15, also wt = 2*pi*60.*t

Will this work in MathCad 15.

Sure. Valery simply used a new variable and named it wt. This is not the product of w and t!

What kind of values are the limits 0 and 3 of your integral? With Valery's approach they are unitless wt values and correspond to t=0 and t=3/w.

If the limits are time values, probably seconds, you would have to replace d(w*t) by w*dt because of

[ptc-4493261]

Many thanks, I have got it.

Vijay