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At which value n the optic focus of lens is a geometric focus too?
See please two pictures and two Prime 3.1 sheets in attach.
Solved! Go to Solution.
I have the function but with y as one more argument.
How can I delete y? Substitute y=1?
the function n (a, b, y) has a pole at y = 0. So you have to exclude the pole in order to draw a graph.
Yes - a pole! How can I show that n(a, y)=sqrt(2)?
How cam I delete in n(a, b) function? One way - insert 1 on the place y?
> How cam I delete in n(a, b) function? One way - insert 1 on the place y?
Yes, or in Prime you better use NaN which unfortunately is not valid in Mathcad 15's 3D plots
Thanks, Werner, I knw it.
But how we can show analytical not by plot that n(a)=sqrt(2)
> Thanks, Werner, I knw it.
So why did yo ask how to get rid of the pole in the plot??
> But how we can show analytical not by plot that n(a)=sqrt(2)
Doesn't your plot show that it isn't exactly sqrt 2 ??
EDIT: Looks that what we see here are numerical round offs.
I was not able to make Mathcad do the symbolic simplifications with general varaibles but at least for specific values (as long as a=b>=0):
Wasn't your question
> > But how we can show analytical not by plot that ...
It is a question!!!
I am preparing an article "Second optical property of hyperbola".
Would you like be a coauthor?
In this article
https://cdn2.mti.edu.ru/cloudofscience/CoS_3/CoS_3_396.pdf
I have only pointed "Thanks, Werner, for help!"
No, I was just confused that you closed the thread even though no full symbolic solution to your question was found.
Werner Exinger написал(а):
Wasn't your question
> > But how we can show analytical not by plot that ...
???
I don't see the correlation to n(a,b)=epsilon(a,b) for y=1, which is what you wanted to show (or at least thats what I got the impression you wanted to show with your plot).
Maybe I am missing the point!?
It is a new solution
ValeryOchkov написал(а):
Werner Exinger написал(а):
Wasn't your question
> > But how we can show analytical not by plot that ...