The label is undefined

[YA_10963798]

Hi there,

Any ideas why this is wrong? I made f as function of M in order to define it 

Regards

Yusra

[Fred_Kohlhepp]

Try getting rid of the following equals sign in the function definition

[YA_10963798]

still the same 

[StuartBruff · Accepted solution]

You've still got the "=" sign at the end of the function definition, Yusra.  You need to go to the very end of the function definition (Fn-right-arrow), then press Backspace twice.  That should remove the equal sign.

Stuart

[YA_10963798]

So I can't put (=) in the function . Thank you for that I didn't know  

Now I have this another error that I always get . Can you explain to me how to tackle it 

[StuartBruff]

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@YA_10963798 wrote:

So I can't put (=) in the function . Thank you for that I didn't know  

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No worries.

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@YA_10963798 wrote:

Now I have this another error that I always get . Can you explain to me how to tackle it 

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Without the worksheet, I'd be flying blind, but my first airport of call would be to check whether dz_ontgr is the same length as g`_ontg.

Stuart

[Werner_E]

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@YA_10963798 wrote:

So I can't put (=) in the function .

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Not after a function DEFINITION.

An = means a numeric evaluation. Which numeric result would you expect here:

Prime can't know which value to use for "x". Even if a variable "x" is defined in front it won't work, because the "x" used in the right hand side of the function definition is NOT the "x" you may have defined in front but rather is the "x" used on the left hand side of the definition (formal function argument).

So when you DEFINE a function you can't evaluate this definition numerically. But after the definition, when you CALL the function providing a specific value for the formal argument you evaluate this function call numerically.

Actually you CAN evaluate a function definition using symbolic evaluation.

But this will not always work OK. If the function definition contains a boolean expression using the function argument(s) it can't decide its truth value without knowing specific values and so will refuse to evaluate symbolically

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Now I have this another error that I always get . Can you explain to me how to tackle it 

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I also suspect that vector dz_ontgr contains not more elements than vector σ'_ontg.

So when in your loop "i" reaches the index of the last value of σ'_ontg, there is no element with index i+1 in vector dz_ontgr.

Probably the same applies to vector γ'_ontg.

If all the mentioned vectors are of the same length the error should go away if you use    for i ∈ ORIGIN..last(σ'_ontg)-1

The resulting vector returned by your function will have one element less than the vectors used. You have to decide if that's what you need.