> Find the equation of a line that is in both slope
> intercept form and standard form?
> Example: Passes through (1,3) with a slope of 3
Point-Slope Form
y - y0 = m�(x - x0)
We have:
(x0,y0) = (1,3)
m = 3
Substitute
y - 3 = 3�(x - 1)
Simplify
y - 3 = 3�x - 3
y = 3�x
That is Slope-Intercept Form.
y = m�x + b
In our case, b = 0, so it may look a little odd.
Standard Form may be
A�x + B�y + C = 0
In our case, a simple adjustment from the Point-Slope form gives:
3�x - y = 0