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Absolute Value

jenny29
4-Participant

Absolute Value

I am having an issue with finding the max value of positive and negative values.  I want it to always pick the highest integer but to have it's sign remain the same.  

 

For instance,

x=10, y=15, z=-20 are my numbers calculated that 

 

t:=550*[max(x,y,z)] -p is depended on.

 

 if I do r:= max(x,y,z) it will state that r=15 when I need it to pick the worse case for an equation it will be integrated in later on. 

 

if I do r:= max(IxI,IyI,IzI) it will state r=20 but not -20 cause of the absolute value.

 

Is there a different approach I can do where I wouldn't have to use solve for t for each single case and pick the max absolute value of all three?

1 ACCEPTED SOLUTION

Accepted Solutions
LucMeekes
23-Emerald III
(To:jenny29)

Define your own function maxabs:

LM_20180130_MaxAbs.png

Success!
Luc

View solution in original post

6 REPLIES 6

max(|x|,|y|,|z|)=max(x,y,z)

This is fallible but works most of the time

if test is true you have a positive number
if test is false you have a negative number

LucMeekes
23-Emerald III
(To:jenny29)

Define your own function maxabs:

LM_20180130_MaxAbs.png

Success!
Luc

Hi Luc. I guess that your solution is correct, just a margin note: If x = max(A) then -x = min(-A). 

Best regards.

 

Alvaro.

Here are my 2 cents

 Bild.PNG

 
jenny29
4-Participant
(To:LucMeekes)

When I do that, it tells me that "these values must all be of one type."  

 

I am not sure what that means.

jenny29
4-Participant
(To:jenny29)

Actually I was able to make it work with your method, Luc. thank you.  My issue was that I was mixing {2,1} variables with {1,1} when what I needed to do first is find the maxabs of the {2,1} and then combine them all in one matrix to find the total maxabs of (B).  It's a bit longer the steps but it gives the correct solution. 

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