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How to define shortly to highly variable dependent equation on mathcad 15

citkit
2-Guest

How to define shortly to highly variable dependent equation on mathcad 15

Hi
ı need to take some plot and ı start to define eqn,

first eqn dependent one variable

second eqn dependent 2 variable

third eqn dependent 3 variable 

and it is going increase thus the equation will be very long

is there any thing to shortly define this kind of eqn?

 

thank youmathcad852.png 

1 ACCEPTED SOLUTION

Accepted Solutions
LucMeekes
23-Emerald III
(To:citkit)

I get this funny feeling that the C1 you are using the definition of the function C3(C1)  is the C1 function that is defined on the first row, etc.

So actually what you want to accomplish is this:

LM_20171210_Variables.png

That is you may have a complicated function, but it is of a single variable....

 

Success!
Luc

View solution in original post

7 REPLIES 7
Werner_E
24-Ruby V
(To:citkit)

Its unclear what you are trying to ask and your screenshot does not show a single equation and no function definition either (which seems to be what you mean by "equation").

Maybe its best if you try to show what you are asking for with a simplified example.

in the picture i take screen shoot of first equaiton set. in the stage is not proble define like C3(C1(theta12)) but after same stage ı get 5 dependet variable equation, and ı need to define shortly this equaiton.

matcah2.png

LucMeekes
23-Emerald III
(To:citkit)

All your many variables, could be just two or three vectors.

Success!
Luc
Werner_E
24-Ruby V
(To:citkit)

You may define

C3(x):=-2*C1(x)+a4

Of course you can use theta12 as formal argument instead of x. The name of the formal argument is not important.

Make the same with C4 and define

C5(x):=-C2(x)^2-C1(x)^2-a4^2+a3^3

etc.

 

LucMeekes
23-Emerald III
(To:citkit)

I get this funny feeling that the C1 you are using the definition of the function C3(C1)  is the C1 function that is defined on the first row, etc.

So actually what you want to accomplish is this:

LM_20171210_Variables.png

That is you may have a complicated function, but it is of a single variable....

 

Success!
Luc

Thank you for your attention, i solve the problem like above 🙂
VladimirN
24-Ruby II
(To:citkit)

Please attach your Mathcad worksheet (in archive file) to the message.

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