1 ACCEPTED SOLUTION
Accepted Solutions
From what I see you have this (assuming your formulation is correct):
Which means you have a function T(t) which is found from the function u2(t) by first taking the derivative of u2(t) with respect to time: u'(t)=d/dt of u(t). Then square the resulting function squ'(t)=u'(t)*u'(t). Then multiply the result with a constant (assuming that a, b, and the three m's are known). This should be simple, provided that u2(t) is given...
Are you sure you don't need a second derivative of any functions u and v, rather that the first derivative squared...?
Success!
Luc
From what I see you have this (assuming your formulation is correct):
Which means you have a function T(t) which is found from the function u2(t) by first taking the derivative of u2(t) with respect to time: u'(t)=d/dt of u(t). Then square the resulting function squ'(t)=u'(t)*u'(t). Then multiply the result with a constant (assuming that a, b, and the three m's are known). This should be simple, provided that u2(t) is given...
Are you sure you don't need a second derivative of any functions u and v, rather that the first derivative squared...?
Success!
Luc
Hi, Luc
So by this step,
Is it possible to let Mathcad derive T(t) with respect to du2(t)/dt?
Which will result in:
It is to set du2(t)/dt as the argument and the others (including u2(t), if exists) as constants.
Thank you
Best
Shawn
Hi Shawn,
No, If you feed that first expression AND u2(t) to Mathcad it will take the deriverative of u2(t), then square it and multiply the resulting function with the constant involving a, b and the three m's. The result you mention is NOT obtained.
Observe my question/comment at the end of my first reply:
Success!
Luc
