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New triangle

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Emerald IV

New triangle

Triangle.png

4 REPLIES 4
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Re: New triangle

Sneaky, Valery!

 

A complex modulus operator, as opposed to real square root operator, should sort it out.

 

Stuart

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Re: New triangle

 

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Pythagoras theorem is valid when using component modulus only.

When using geometric rules it is absurd to take consideration of -1 mulltiplicant (i^2) /Avdo

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Re: New triangle

 

T1.pngT2.png

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Re: New triangle

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