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Not sure why the position of tan(beta) definition changes the evaluation of beta

bg6
Newbie

Not sure why the position of tan(beta) definition changes the evaluation of beta

3 REPLIES 3

Re: Not sure why the position of tan(beta) definition changes the evaluation of beta

It's hard to debug a picture. I assume you have chosen to display an assignment as just "=", rather than as ":=". If so, then the problem is that you when you write tan(beta):=, you have redefined the built-in function for tan(). As it happens, since beta does not appear on the rhs of the definition, it's a function that will always return the same value.

If that's not the problem then please post the worksheet (click on "Use advanced editor" at the top right of the edit dialog)

Re: Not sure why the position of tan(beta) definition changes the evaluation of beta

Thanks.  Did not realize I was redefining tan() function.

Re: Not sure why the position of tan(beta) definition changes the evaluation of beta

And also note that Mathcad works from TOP & LEFT, meaning that variable definitions must be above or left of any function(s) to operate as expected.

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