A square uniform raft, 18m by 18m, of mass 6800kg, is used as a ferryboat. If three cars, each of mass 1200kg., occupy its NE, SE and SW corners, determine the CM of the loaded ferryboat.
Hi, well thats the question. the book gives me one formula that is appropriate which states:
x CM = mx (A) + mx (b) / m(A)+m(B)
That formula seems to work in one dimensions. So then I was thinking putting the quesiton in 2 dimension x and y. So Id try to find the center of mass along one axis of the boat and then use x and y as components to find the CM. Although I failed trying.
here the answer:
(1.04m, -1.04m) relative to the centre of the raft
It's just another mass. By symmetry the center of mass of the boat must be at its center. So for the purpose of calculating a center of mass of the whole system it behaves as a point mass at its center.