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12-14-2015
08:36 AM

12-14-2015
08:36 AM

Hello, Everyone.

How are they different ?

Thanks in advance for your time and help.

Regards.

Solved! Go to Solution.

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12-14-2015
04:31 PM

12-14-2015
04:31 PM

I think it's a quirk of the Mupad symbolic engine.

In Mathcad 11 the (Maple) symbolic engine produces the following quirky output:

It appears that e or the exp() function has a special meaning:

The first line gave the error "No symbolic result was found". which is understandable because e^x is always immediatley translated to exp(x). But the second line then surprises with the same error message; unexpected because exp(i)^i indeed IS in there. At least (third line) with any other variable we get expected results, giving clues for the way to deal with e as shown in the fourth line.

Luc

3 REPLIES 3

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12-14-2015
09:16 AM

12-14-2015
09:16 AM

Re: (e^1i)^1i simplify ==> e^(-1) and (a^1i)^1i simplify ==> (a^1i)^1i . How are they different ?

Hello! you could write it so:

It performs the exponential only if a = e. or to powers of e, for example a=3:

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12-14-2015
04:31 PM

12-14-2015
04:31 PM

I think it's a quirk of the Mupad symbolic engine.

In Mathcad 11 the (Maple) symbolic engine produces the following quirky output:

It appears that e or the exp() function has a special meaning:

The first line gave the error "No symbolic result was found". which is understandable because e^x is always immediatley translated to exp(x). But the second line then surprises with the same error message; unexpected because exp(i)^i indeed IS in there. At least (third line) with any other variable we get expected results, giving clues for the way to deal with e as shown in the fourth line.

Luc

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12-14-2015
11:33 PM

12-14-2015
11:33 PM

Re: (e^1i)^1i simplify ==> e^(-1) and (a^1i)^1i simplify ==> (a^1i)^1i . How are they different ?

Thanks for your response, P.M. and Luc.

It seems my Mathcad 14 don't work (accept) with:

because :

furthermore :

and I wish learning,wish having your help in Mathcad 14.

Best Regards

Loi.