graphs

[zara-disabled]

How do you chart a graft when you have an equation
like: 2x-5y=_3?

Find a y value of b in 2y=-7x+3b so that the y--intercept of its graph will be (0,-13).


The cost C(d), in dollars, of a taxi ride in Pelham is given by C(d) = 0.75d + 2, where d is the number of miles traveled.

[mzeftel]

Are you asking how to graph 2x - 5y = -3 in StudyWorks? If so, here's the answer.

First you need to redefine the equation so it is in the slope-intercept form of a line, y = mx + b.

For your problem, define A = 2, B = -5, and
C = -3.

Slope or m = -A/B or m = -2/-5 or m = 2/5

the y-intercept = C/B or b = -3/-5 or b = 3/5

Then you can rewrite your equation as

y = 2/5 x + 3/5

To graph this line in StudyWorks, just type in the right side of the equation, 2/5x + 3/5. Select it, and choose insert graph.

You'll see the plot appear after you press return.

The lesson in Algebra on Slope-Intercept Form should be helpful. You can even substitute your values for A, B, and C in the example.