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10-05-2003
03:00 AM

10-05-2003
03:00 AM

help on equivalent resistance

I understand how to find equivalent resistance, but I'm having so much trouble with this problem; I couldn't get the right answer even though I spend hours to do this problem, please help me.

The picture to the problem is the attachment

Find the equivalent resistance of the circuit shown in the attachment.

Thanks,

abk511

The picture to the problem is the attachment

Find the equivalent resistance of the circuit shown in the attachment.

Thanks,

abk511

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10-05-2003
03:00 AM

10-05-2003
03:00 AM

help on equivalent resistance

On 10/5/2003 1:07:51 AM, abk511 wrote:

>I understand how to find

>equivalent resistance, but I'm

>having so much trouble with

>this problem; I couldn't get

>the right answer even though I

>spend hours to do this

>problem, please help me.

>

>The picture to the problem is

>the attachment

>

>Find the equivalent resistance

>of the circuit shown in the

>attachment.

>

>Thanks,

>abk511

The two pairs of resistors

4 ohm + 2 ohm and 6 ohm + 3 ohm should be combined into 6 ohm and 9 ohm respectively. This gives you two "delta" networks.

You'll need to convert one of the deltas into a "wye" configuration. This can be done by considering the equivalent resistance across each pair of connections in the delta with the 3rd connection disconnected and equating that with the equivalent two resistance in the wye network. It's fairly straight-forward. If you run into difficultly, this link shows the correct answer:

http://www.ece.pdx.edu/~ece2xx/ECE221/Lectures/ResistiveCircuitsx4.pdf

Once that's done, your left with a parallel circuit of series resistances.

TTFN,

Eden

>I understand how to find

>equivalent resistance, but I'm

>having so much trouble with

>this problem; I couldn't get

>the right answer even though I

>spend hours to do this

>problem, please help me.

>

>The picture to the problem is

>the attachment

>

>Find the equivalent resistance

>of the circuit shown in the

>attachment.

>

>Thanks,

>abk511

The two pairs of resistors

4 ohm + 2 ohm and 6 ohm + 3 ohm should be combined into 6 ohm and 9 ohm respectively. This gives you two "delta" networks.

You'll need to convert one of the deltas into a "wye" configuration. This can be done by considering the equivalent resistance across each pair of connections in the delta with the 3rd connection disconnected and equating that with the equivalent two resistance in the wye network. It's fairly straight-forward. If you run into difficultly, this link shows the correct answer:

http://www.ece.pdx.edu/~ece2xx/ECE221/Lectures/ResistiveCircuitsx4.pdf

Once that's done, your left with a parallel circuit of series resistances.

TTFN,

Eden