Hello why can I not solve this I want to solve Q to me in [m^3/hr]
Because you cannot add apples to pears; or subtract them.
Under the root you've got 2801.0 (unitless) and
which calculates to something like 2056 m (so this one has units!)
Either 800 must have a unit of 1/m, or 2801 must be metres; or you will not be able to subtract one from the other.
Going back to your quadratic: If Q has a unit of m^3/hr, then 0.2 must have that same unit, and 3.5 must have a unit of m^6/hr^2. Then, in order to get the equation right, DeltaPpump/rho*g must also have a unit of m^6/hr^2, which it does not have (it has a unit of m, as I stated above).
All this is under the assumption that the formulae you are working with are physically based, that is, they are derived from a sound physical understanding and modelling of the problem. If thta's not the case, and this formula is experimentally determined, such that it 'happens to work', then you are better off stripping the units.
You expect Q in m^3/hr?
If the equation is physically based and unit balanced, then the coefficients must have the units you see in the picture below.
Chances are that its an empiric formula and then you should strip off the units by dividing the input values by the units, the empiric formula expects them to be in.
This is a beautiful illustration of why we need "UnitsOf". 😉
"UnitsOf" does not help if the emiric formula expects a variable in a different than the default unit.
Personally I'd prefer to use "SIUnitsOf" or rather chosing the units myself for better control as shown above. Otherwise a change of the unit system of the sheet has the effect of different results of the very same sheet.