>Re-think your problem. If Ck+Dk=1 for each "k" then they play no role in "v", which is simple the summation of 3k^2-3k+1 from 1 to "N". With "N" limited to a few values, you can simple calculate all "A" 12 possible values...[Al]<<br> ____________________________________
Maybe not exactly like that. What's under Sigma is N�. If multiplied by C, D, E it will have the meaning found in the vector sum [k of C+D+E from a user valued system. As given in the work sheet, the solution is unique 2/3, but C+D+E may be found as anything happening in the user addressed vector sum so that a general solution is now:
That's how the problem it appears not knowing more to be interpreted.
jmG