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## polar transformation

hi guys,

Is there a way to convert a complex function to its polar form easily?

Say, a+bi >> sqrt(a^2+b^2) angle: atan(b/a)

Also, is there an easy way to find and assign a variable the conjugate of the complex function (without having to retype all the way)

attached is a simple problem (err solution) which i made.

notice that i have to rewrite just to get the conjugate..

and i can't outrightly transform it to phasor..

thanks..

1 ACCEPTED SOLUTION

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## Re: polar transformation

 Is there a way to convert a complex function to its polar form easily?Say, a+bi >> sqrt(a^2+b^2) angle: atan(b/a)Also, is there an easy way to find and assign a variable the conjugate of the complex function (without having to retype all the way)attached is a simple problem (err solution) which i made.notice that i have to rewrite just to get the conjugate..and i can't outrightly transform it to phasor..thanks..

Yes. Go to Help and search for the word 'polar'. From the results, select the page 'functions for complex numbers'; this describes the arg function and modulus function. Then goto the linked Quicksheet "Complex Numbers: Polar Notation". This gives examples of their use and gives a pair of (user-defined) functions that handle transformation between the polar and rectangular forms.

You can get the complex conjugate by using the built-in conjugate operator (key stroke " in M13).

As an aside, it is generally better to post a worksheet rather than a pdf file - save somebody the effort of typing in what they see and 'print outs' can mask subtle errors, such as implicit multiplication or incorrect choice of index type (ie, index v literal). Ideally, post the worksheet in the version you use and the earliest version Mathcad will let you save as (the latter gives you a much wider audience as Mathcad worksheet format s are not generally backward compatible), eg Mathcad 11 will not read Mathcad 13 xmcd files).

4 REPLIES 4
Highlighted

## Re: polar transformation

 Is there a way to convert a complex function to its polar form easily?Say, a+bi >> sqrt(a^2+b^2) angle: atan(b/a)Also, is there an easy way to find and assign a variable the conjugate of the complex function (without having to retype all the way)attached is a simple problem (err solution) which i made.notice that i have to rewrite just to get the conjugate..and i can't outrightly transform it to phasor..thanks..

Yes. Go to Help and search for the word 'polar'. From the results, select the page 'functions for complex numbers'; this describes the arg function and modulus function. Then goto the linked Quicksheet "Complex Numbers: Polar Notation". This gives examples of their use and gives a pair of (user-defined) functions that handle transformation between the polar and rectangular forms.

You can get the complex conjugate by using the built-in conjugate operator (key stroke " in M13).

As an aside, it is generally better to post a worksheet rather than a pdf file - save somebody the effort of typing in what they see and 'print outs' can mask subtle errors, such as implicit multiplication or incorrect choice of index type (ie, index v literal). Ideally, post the worksheet in the version you use and the earliest version Mathcad will let you save as (the latter gives you a much wider audience as Mathcad worksheet format s are not generally backward compatible), eg Mathcad 11 will not read Mathcad 13 xmcd files).

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## Re: polar transformation

Check first your formulas and attach a work sheet with a circuit diagram.

jmG

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## Re: polar transformation

attached are the problem and the mathcad file..

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## Re: polar transformation

Sorry, no collab does homework, use your book.

1. Why enlarge a scanned image from book ?

2. The quiz is that there is no answer because there is no question.

Alternating sources have no polarity.

Maybe not because the resistive load is just heating the birds on the line.

Invent some resistive load and work by the examples in the book.

If cos f is 0.8575 and not the same as cos f Z, can you conclude the

resistive load ? Can you check if pf 0.8575 is cos f for Z.