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simplify

simplify

Hi
can you help simplify this problem:

(3a^4b^3c^2) divide that by 1/6
plus (9abc^16) minus 21.396 divide by (a^16b^21c^4)

or
(3a^4b^c^2)+(9abc^16)-21.396
1/6 (a^16b^21c^4)

thanks
1 REPLY 1

simplify

On 11/14/2002 1:16:00 AM, joie-ko wrote:
>Hi
>can you help simplify this
>problem:
>
>(3a^4b^3c^2) divide that by
>1/6
>plus (9abc^16) minus 21.396
>divide by (a^16b^21c^4)
>
>or
> (3a^4b^c^2)+(9abc^16)-21.396
> 1/6 (a^16b^21c^4)
>
>thanks

(3a^4b^3c^2) / (1/6) + [(9abc^16)-21.396] / (a^16b^21c^4)

Dividing by 1/6 is the same as multiplying by it.

(18a^4b^3c^2) + [(9abc^16)-21.396] / (a^16b^21c^4)

There is not really anything that can be done to simplify the second part. Are you looking for anything in particular?

Craig
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