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11-26-2002
03:00 AM

11-26-2002
03:00 AM

word problems

I need help on this word problem. Can you do it in steps so I can understand these type of word problems?

If the product of 5 and a number is increased by 9 and this sum multiplied by 3, the result is 11 greater than the opposite of the number. Find the number.

thx

If the product of 5 and a number is increased by 9 and this sum multiplied by 3, the result is 11 greater than the opposite of the number. Find the number.

thx

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11-26-2002
03:00 AM

11-26-2002
03:00 AM

word problems

>If the product of 5 and a

>number is increased by 9 and

>this sum multiplied by 3, the

>result is 11 greater than the

>opposite of the number.

Learn to be systematic and consistent. Do NOT make the mistake of considering each such problem a new experience. Develop a logical process and stick with it. This one works for me:

>number is increased by 9 and

>this sum multiplied by 3, the

>result is 11 greater than the

>opposite of the number.

Learn to be systematic and consistent. Do NOT make the mistake of considering each such problem a new experience. Develop a logical process and stick with it. This one works for me:

- Name Stuff
- Decode the Problem Statement
- Solve
- Check

- Name Stuff: "Find the Number." Okay, the number is "N".
- Decode the Problem Statement: (5�N + 9)�3 = -N + 11
- Solve: 15�N + 27 = -N + 11

16�N + 27 = 11

16�N = -16

N = -1 - Check: (5�(-1) + 9)�3 = (-5 + 9)�3 = 4�3 = 12

-(-1) + 11 = 1 + 11 = 12

Done

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11-27-2002
03:00 AM

11-27-2002
03:00 AM

word problems

The hard part for most students is finding the equation from the word problem. It helps to write it out step by step.

If the product of 5 and a number is increased by 9 and this sum multiplied by 3, the result is 11 greater than the opposite of the number.

If the product of 5 and a number: 5*N

is increased by 9: + 9 so 5*N + 9

this sum multiplied by 3: 3*(5*N + 9)

the result is 11 greater: = 11 +

than the opposite of the number: -N

Put it all together to get

3*(5*N + 9) = 11 + (-N)

Mona

If the product of 5 and a number is increased by 9 and this sum multiplied by 3, the result is 11 greater than the opposite of the number.

If the product of 5 and a number: 5*N

is increased by 9: + 9 so 5*N + 9

this sum multiplied by 3: 3*(5*N + 9)

the result is 11 greater: = 11 +

than the opposite of the number: -N

Put it all together to get

3*(5*N + 9) = 11 + (-N)

Mona