What @Rocko commented is correct, DD is day of the year.
To add more detail, I will add an excerpt from my snippet documentation - please check the link:
Description: returns a datetime as a string, formatted in a specific way
The format used is the one from the joda library, and specific examples can be seen at http://www.joda.org/joda-time/apidocs/org/joda/time/format/DateTimeFormat.html
Example Usage (we get the current date and we output as a string, formatted in a specific format):
// dateValue:DATETIME
var dateValue = new Date();
// dateFormat(dateValue:DATETIME, dateFormat:STRING):STRING
var result = dateFormat(dateValue, "yyyy-MM-dd HH:mm:ss");
DD is probably day of year. have you tried "dd"?
Also, next time please try to provide a proper description of the issue and a question to the audience, instead of just a headline and a screenshot.
It's much more polite and people are more inclined to help you.
What @Rocko commented is correct, DD is day of the year.
To add more detail, I will add an excerpt from my snippet documentation - please check the link:
Description: returns a datetime as a string, formatted in a specific way
The format used is the one from the joda library, and specific examples can be seen at http://www.joda.org/joda-time/apidocs/org/joda/time/format/DateTimeFormat.html
Example Usage (we get the current date and we output as a string, formatted in a specific format):
// dateValue:DATETIME
var dateValue = new Date();
// dateFormat(dateValue:DATETIME, dateFormat:STRING):STRING
var result = dateFormat(dateValue, "yyyy-MM-dd HH:mm:ss");
It appears your question has been answered. If you agree, please mark the appropriate response as the Accepted Solution.
If you still have questions, please let us know so we can continue to provide support.
Regards.
--Sharon
