>A car enters the freeway with
>a speed of 6.5 m/s and
>accelerates uniformly for 3.3
>km in 3.7 min.
>How fast is the car moving
>after this time? Answer in
>units of m/s.
3.7 minutes=222 seconds.
At 6.5 m/s, distance travelled is 1443 m. Since total distance was 3300 m, 1857 m must be from the acceleration, so 1857=1/2*acc*t^{2}.
Hopefully, you do recognize that I simply broke up:
x(t)=v_{0}t+1/2*acc*t^{2}
into two parts?
TTFN,
Eden