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1-Newbie

## Newtons Laws and Connected Particles

HI, Im new here can anyone give me a solution to this problem:

A block X is on top of a block Y. The block Y is being on one side by a force P. the coefficient of friction between the block x and the block y is 0.35, the coefficient of friction between the block Y and the horizontal table that it rests on is 0.3. What is the maximum value for P for which X begins to slip on Y.

thanks so much,
Sinewave.
1 REPLY 1
On 11/24/2007 4:05:01 PM, Sinewave wrote:
>HI, Im new here can anyone
>give me a solution to this
>problem:
>
>A block X is on top of a block
>Y. The block Y is being on one
>side by a force P. the
>coefficient of friction
>between the block x and the
>block y is 0.35, the
>coefficient of friction
>between the block Y and the
>horizontal table that it rests
>on is 0.3. What is the maximum
>value for P for which X begins
>to slip on Y.
>
>thanks so much,
>Sinewave.
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Consider block x. The force generating its acceleration is provided by static friction.
The maximum force is 0.35Mxg = Mx accel, by Newtons law. You now know the acceleration: accel = 0.35 g.

Now consider both blocks: They have this acceleration which is due to the net applied force. Thus P - 0.3(Mx + My) = (Mx+My) accel
Substitute for accel and solve for P.

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Physics: Common Sense made Obscure by Mathematics Don Sparlin
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