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Simplifying Rational Expressions

MusicMonkey-dis
1-Newbie

Simplifying Rational Expressions

I do not understand if the following equation can be simplified.

x squared - 3z squared
------------------------------------
2x squared - 7xz + 3z squared

If it can be simplified, how? In general, when a question like this comes up if there is an equation in the numerator that is not in brackets and two separate equations separated by brackets, can it be simplified. THANK YOU VERY MUCH. 🙂
8 REPLIES 8

>x squared - 3z squared
>------------------------------
>2x squared - 7xz + 3z squared
>
>If it can be simplified, how?
>In general, when a question
>like this comes up if there is
>an equation in the numerator
>that is not in brackets and
>two separate equations
>separated by brackets, can it
>be simplified. THANK YOU VERY
>MUCH. 🙂

Look more closely at the denominator:
2x2 -7xz+3z2
=(2x-z)(x-3z)

TTFN

Could it be simplified to :

x + 3z
---------
2x - z


or is the furthest it can be simplified

x squared - 3z squared
-----------------------------------
(2x - z) (x - 3z)


Thank you 🙂

Not unless there's a typo; you would have needed x2-9z2 to get (x-3z)(x+3z)

TTFN

could you reduce the numerator because of like terms by cancelling out the x - 3z in the denominator.

For example:

x squared - 3z squared
-----------------------------------
(2x-z) (x-3z)

could it become

x - 3z
--------
(2x-z)


If no why not?

>could you reduce the numerator
>because of like terms by
>cancelling out the x - 3z in
>the denominator.
>
>For example:
>
>x squared - 3z squared
>------------------------------
>-----
>(2x-z) (x-3z)
>
>could it become
>
>x - 3z
>--------
>(2x-z)

[x� - (3z)�]/[(2x-z) (x-3z)] = [ (x-3z) (x+3z)]/[(2x-z) (x-3z)] = (x+3z)/(2x-z)

You can cancel it as you expected, but note that you will have an x+3z on top.

Craig

I was wondering, in this question to simplifying rational expressions ??

Find (-6x^2 - 4xy + 8x)/(2x)

do they want me to find out what the variables are, or do they want me

to do something else with it? That is the exact way they have the

question written down.

This thread in over four years old, you might want to start a new thread.

Mike

Ok....Thnx mike...for the reply......

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