How to add information button in table builder to show the information about that object

[RS_10128209]

I have added this but not working

ColumnConfig c6= ccf.newColumnConfig("infoPageAction", true); //for i button
c6.setInfoPageLink(true);
c6.setDefaultSort(true);
tc.addComponent(c6);

[HelesicPetr]

Hi @RS_10128209 

Something has to be wrong in your code. 

create columnconfig is correct. Add the compotnent to the table config is correct.

why do you try to sort by an infobutton? 

Following example works for me perfectly.

tableConfig.addComponent(configFactory.newColumnConfig("infoPageAction", true));

try to debug the code by stopping the method line by line and control what is in tableConfig object

PetrH

[RS_10128209]

Thanks @HelesicPetr for reply 

but its creating blank column with only name 

[HelesicPetr]

Hi @RS_10128209 

What version do you use?

What kind of object is show in the table? is it your type or some general type?

Is it Link object or is it normal object as WTPart. 

Depends on your configuration. I guess that you will need to define own DataUtility which creates correct information button because OOTB DU can not find correct object to build the button. 

PetrH 

[RS_10128209]

I have created some subtypes of part , i have created objects of that type 

I want to navigate to that objects .

Im using windchill 12.0 

[HelesicPetr]

Hi @RS_10128209 

What is your row object exactly. Check it with &jcaDebug=1 option in an URL

You should see something like this

As you can see there is CustomInfoPageActionDataUtility which cares how the info button is shown.

PetrH

[RS_10128209]

Mine showing this

[HelesicPetr]

Column id name? is not correct.

[RS_10128209]

ColumnConfig c1 = ccf.newColumnConfig("name", true);
c1.setInfoPageLink(true);
c1.setLabel("Name");
tc.addComponent(c1);

i have used this

[HelesicPetr]

Do you want to get infoButton or name ? The name is shown as I see.

[HelesicPetr]

hi @RS_10128209 

Try to set target object

c6.setTargetObject("part");
and
c6.setDataUtilityId("infoPageAction");

btw. in my case and own tablebuilder, I needed to create own DataUtility that cares about the showing the information icon button. OOTB didn't work for me.

But in my case a row object is oid not part. 

PetrH