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15-Moonstone

## Cut in two piece

Hello

I do a test simply with a washer, see the sketch enclosed.

I do the simulation with the whole puck and then with half of the puck as well as half of the load.

And I get not the same result to Von Mises:

Entire puck 750.0 [MPa]

Puck half 642.0 [MPa]

When you cut a piece in half to do more than the symmetrical connection.

Kind regards.

Denis

7 REPLIES 7
12-Amethyst
(To:DenisJaunin)

Hi Denis,

Do the contact forces balance/add up?

How is your F1 & F2 applied?

atb

15-Moonstone
(To:346gnu)

Good morning Charles.

In reality the force F1 is the support reaction of the force F2.

I have an F1 support that is done on a dia crown. Ext of 42.0 [mm] and dia int of 30.0 [mm].

The force F2 of 30 [KN] acts on a ring of dia ext of 30.0 [mm] and dia int of 23.0 [mm]

Thickness of washer 3.25 [mm]

Cordially.

Denis

1-Newbie
(To:DenisJaunin)

test 2d

Regards

Paul

15-Moonstone
(To:pkloninger(cust)

Hello Paul,

Thanks for this very interesting answer in its design, I take

good note.

I am attaching a picture of the representation of the puck split in half with the

a half load whose constraints are not identical.

As stated in the first post.

I may be forgetting to do something when you cut a piece by

its plane of symmetry.

Kind regards.

Denis

1-Newbie
(To:DenisJaunin)

Hello Denis,

OK, maybe 2d contact better?

15-Moonstone
(To:pkloninger(cust)

Hello

Thank you for your new shipment.

I'm going to watch it.

But what I still don't understand, is why when I simulates half a piece by the plane of symmetry, I do not get the same results.

Kind regards.

Denis

1-Newbie
(To:DenisJaunin)

Hello Denis,

your model is wrong, half too,

not constraints possible, contact only.

Regards

Paul

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