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Deformed shape of a bar in torsion

TadDoxsee
1-Newbie

Deformed shape of a bar in torsion

The following question comes up once every couple of years, so it makes a good blog topic. The question usually goes something like this.

“When I twist a circular shaft, why does Simulate show that its radius grows?  It shouldn’t, right?”

Here’s a picture of a circular shaft that is fixed on one end and with a moment (defined with a total load at point) applied at the other end.

torsion_bar1.png

If you run the default static analysis and look at the deformed shape, it looks like the radius grew.

linear_fringe.png

But that can’t be right.

Actually, this is a well-known phenomenon, and is due to the linear approximation used in the default static analysis. In a linear analysis, displacement and rotations are assumed to be small.  When rotations are small, the displacement of a point on a disc that rotates is approximately the rotation (measured in radians) multiplied by the distance of the point from the center of rotation. When showing the deformed shape of such a rotation in Simulate, all displacements are exaggerated by scaling.

This figure shows the original shaft in grey.  When it rotates, the black points on the boundary of the shaft displace to the red points, giving the illusion that the radius of the shaft grew.

circles.png

Because large deformation analysis does not make the approximation that displacements and rotations are small, this phenomenon is not present in large deformation analysis, as shown in this deformed of the fringe of the same analysis run with large deformation.

lda_fringe.png

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