Get Help

Turn on suggestions

Auto-suggest helps you quickly narrow down your search results by suggesting possible matches as you type.

Showing results for

- Community
- :
- Creo (Previous to May 2018)
- :
- Creo Modeling Questions
- :
- Model with simple frustrum - volume calculation wr...

Options

- Subscribe to RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic for Current User
- Bookmark
- Subscribe
- Printer Friendly Page

Auto-suggest helps you quickly narrow down your search results by suggesting possible matches as you type.

Showing results for

Highlighted

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Notify Moderator

03-28-2014
04:36 PM

03-28-2014
04:36 PM

I make a lot of models that involve pyramidal frustrums (transition of a rectangular section to another rectangular section, linearly). Rather than use the measured value calculated by Creo, I thought I'd have a go at calculating the volume directly from the dimensions.

When I check my calculations, the volume calculated directly from the dimensions differs from the Creo analysis result.

I minimized the accuracy value, but still get the exact same result.

Here are my simple values

Base rectangle: 5 X 3 -> Base area: 15

Top rectangle: 4 X 2 -> Top area: 8

Height: 1

Frustrum of a pyramid volume is

Volume = ( Area Base + Area Top + SQRT ( Area Base * Area Top ) ) * Height / 3 = 11.3182

Creo, on the other hand, gives a volume of 11.3333.

Anyone have any insights into this?

This is simple shape, and kind of scares me about what might be happening with more complicated geometry.

Solved! Go to Solution.

1 ACCEPTED SOLUTION

Accepted Solutions

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Notify Moderator

03-28-2014
07:56 PM

03-28-2014
07:56 PM

I think Creo is right.

I'm not sure where the formula came from but ...

L = l_base - ((l_base-l_top)/delta_z) * Z

W = w_base - ((w_base-w_top)/delta_z) * Z

A = L * W =

l_base*w_base

- (l_base*((w_base-w_top)/delta_z) + w_base*((l_base-l_top)/delta_z)) * Z

+ ((l_base-l_top)/delta_z)*((w_base-w_top)/delta_z)*Z*Z

Integrating:

V =

l_base*w_base*Z

- (l_base*((w_base-w_top)/delta_z) + w_base*((l_base-l_top)/delta_z)) * Z*Z/2

+ ((l_base-l_top)/delta_z)*((w_base-w_top)/delta_z)*Z*Z*Z/3

Plugging it all in I get 11.33...

6 REPLIES 6

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Notify Moderator

03-28-2014
07:56 PM

03-28-2014
07:56 PM

I think Creo is right.

I'm not sure where the formula came from but ...

L = l_base - ((l_base-l_top)/delta_z) * Z

W = w_base - ((w_base-w_top)/delta_z) * Z

A = L * W =

l_base*w_base

- (l_base*((w_base-w_top)/delta_z) + w_base*((l_base-l_top)/delta_z)) * Z

+ ((l_base-l_top)/delta_z)*((w_base-w_top)/delta_z)*Z*Z

Integrating:

V =

l_base*w_base*Z

- (l_base*((w_base-w_top)/delta_z) + w_base*((l_base-l_top)/delta_z)) * Z*Z/2

+ ((l_base-l_top)/delta_z)*((w_base-w_top)/delta_z)*Z*Z*Z/3

Plugging it all in I get 11.33...

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Notify Moderator

03-28-2014
09:40 PM

03-28-2014
09:40 PM

Re: Model with simple frustrum - volume calculation wrong

I should be able to simplify the integral to be the same as the original formula, but so far no luck. I looked at the Wikipedia page that showed the derivation of the original formula, but it doesn't yield terms I can yet convert.

I get 11.3182 from the original formula, but don't see the reason for the discrepancy.

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Notify Moderator

03-29-2014
12:48 AM

03-29-2014
12:48 AM

Re: Model with simple frustrum - volume calculation wrong

I got the original formula from the CRC math tables. A handy book from olden times which has all sorts of nice answers to unusual geometry questions. It's an odd conundrum. One would, reasonably, expect any sound mathematical method to yield the same results.

I can see where your integration comes from, and how it gets the number Creo gets. But still, I wonder if I'm missing something crucial about the frustrum...

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Notify Moderator

03-29-2014
12:19 PM

03-29-2014
12:19 PM

Re: Model with simple frustrum - volume calculation wrong

I put the integration solution and original into Excel and tried some experiments.

Case 1: the top and bottom the same; the original formula and mine agree.

Case 2: the top dimensions both zero; the original formula and mine agree.

Case 3: the top length equal to the bottom and the top width to zero the formulas disagree. Since it's simulating a triangle section, the volume should be 1/2 that of Case1. Mine is, but the original formula gives 1/3.

What is interesting is that the original formula doesn't distinguish between the case where the top surface area is zero because it is a point and the case where it is a line.

It may be that the original formula is built on the assumption that the sides all could extend to a single point and is shape independent while the integration handles sides of differing slopes, but only rectangles.

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Notify Moderator

03-29-2014
02:08 PM

03-29-2014
02:08 PM

Re: Model with simple frustrum - volume calculation wrong

I think I figured it out. The frustrum equation, though not described as such, must only apply to a square pyramid, i.e. where L and W are the same for each height, z. When that assumption is applied to the integrated solution, the resultant equation collapses to the one from the CRC tables.

I wish I'd noticed that earlier.

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Permalink
- Email to a Friend
- Notify Moderator

07-11-2017
07:53 AM

07-11-2017
07:53 AM

Re: Model with simple frustrum - volume calculation wrong

Just in the interest of completeness, I needed to document this for some training stuff, so I have a nice illustration of the problem with the mathematical solution employed. Attached is picture of the results.