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1-Newbie

## drawing spiral

Hi how can I draw these spiral using Relations and Pattern features?

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1 ACCEPTED SOLUTION

Accepted Solutions
12-Amethyst

One way is to do a dimension-based pattern a sketch which contains 2 tangent arcs:

Rd75 = 10

Rd74 = 20

Both radii in the sketch are incremented in the pattern definition; so the next instance's smaller arc has the radius as the previous instance's larger arc...

I just sketched this example quickly and it worked out; but I don't know off the top of my head the formula for the increments that achieves the continuous spiral.

10 REPLIES 10
1-Newbie

thank you but how can I draw it using arc and pattern  ?

12-Amethyst

One way is to do a dimension-based pattern a sketch which contains 2 tangent arcs:

Rd75 = 10

Rd74 = 20

Both radii in the sketch are incremented in the pattern definition; so the next instance's smaller arc has the radius as the previous instance's larger arc...

I just sketched this example quickly and it worked out; but I don't know off the top of my head the formula for the increments that achieves the continuous spiral.

1-Newbie
(To:psobejko)

thank you

1-Newbie

There is a small problem

10-Marble

Part of the problem is a spiral is not defined simply as two circular patterned and incremented as you have done they are specified by equations as Steve shows. You might get close with what you are doing but it's not a true spiral.

Creating a datum curve by cylindrical equation will create the most accurate spiral.

There is always more to learn in Creo.
12-Amethyst

In the 1st sketch, the centers and ends of the 2 connected arcs have to all be co-linear.  This means that the arcs are tangent to one another and the tangent line and the two free ends are pointing in the same direction (which is perpendicular to the co-linear line).

Also, to get a continuous "spiral", I think the increment amount in the pattern has to be equal for both radii and its value is 2*(difference in sizes of the radii in the 1st sketch).

7-Bedrock

To make a spiral that behaves according to the original post's attached picture, I would create a datum curve by equation with cylindrical coordinates.

Input IR (Inner radius), N (Number of Turns), PITCH (Pitch)

Setup the equation like this:

/*  r =IR + t * (N * PITCH) , IR = Starting Radius, N = Number of Turns, t [0-1], (N*PITCH) = OR - IR, OR = Outer Radius

r = IR + t * (N * PITCH)

/*  theta = t * N * 360  , theta = angle, t [0-1], N = Number of Turns, 360 = full circle

theta = t * N * 360

/*  z = height  , 0 = flat, t * cos(r) = helical spiral thingy

z = 0

15-Moonstone