1i*ln(1/[e^pi]^1i) simplify ==> -pi and 1i*ln(1/...

lvl107 · ‎Mar 07, 2017

Hello Everyone.

1i*ln(1/[e^pi]^1i) simplify ==> -pi and 1i*ln(1/[e^pi]^1i) = -pi simplify ==> 0 ( Could apply "simplify" in this case ? )

Thanks in advance.

Regards.

-MFra- · ‎Mar 08, 2017

Hi Loi Le,

Okay so?

1iln(1/[e^pi]^1i) simplify ==> -pi and 1iln(1/[e^pi]^1i) = -pi simplify ==> 0 ( Could apply "simplify" in this case ? )