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Jan 11, 2019
01:23 PM

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Jan 11, 2019
01:23 PM

Definite integral evaluation (Fuchs-Sondheimer Resistivity model for Nanowires)

I really appreciate it if someone can help me to double check the following equation by running my sheet in their Mathcad.

It is because the result that I got is the opposite with the result in the paper where the equation comes from.

The decreasing result at small w comes from this part.

This is my sheet.

The original paper: https://journals.aps.org/prb/abstract/10.1103/PhysRevB.61.14215

The equation from the paper (phi and psi should be the same):

the expected result (solid line):

Solved! Go to Solution.

Labels:

ACCEPTED SOLUTION

Accepted Solutions

Jan 12, 2019
11:44 AM

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Jan 12, 2019
11:44 AM

Where did you find the value for Rho0 (to be 2.44 uOhm.cm?) and that phi should be dependent on w (and h) as phi=arctan(w/h) ? I think Rho0 would be rather 6.5 uOhm or so (from Fig 4). It's a bad article because it doesn't specify what phi is, and if phi is really atan(w/h), it should have been spelled out.

I constructed the formula for rho0/rho from the article, resulting in:

For values of w<43 nm Mathcad (11) cannot find a converging solution (TOL=10^-7). And you see I did use phi=atan(w/h). Setting phi to a fixed value (somewhere between atan(1) and atan(10)) doesn't change the graph significantly, at least not such that it turns the hockeystick upside down.

So this gives rho0/rho. This means that with (a constant) rho0, then rho as a function of w etc.. will be:

Sort of what you found.

Success!

Luc

2 REPLIES 2

Jan 12, 2019
11:44 AM

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Jan 12, 2019
11:44 AM

Where did you find the value for Rho0 (to be 2.44 uOhm.cm?) and that phi should be dependent on w (and h) as phi=arctan(w/h) ? I think Rho0 would be rather 6.5 uOhm or so (from Fig 4). It's a bad article because it doesn't specify what phi is, and if phi is really atan(w/h), it should have been spelled out.

I constructed the formula for rho0/rho from the article, resulting in:

For values of w<43 nm Mathcad (11) cannot find a converging solution (TOL=10^-7). And you see I did use phi=atan(w/h). Setting phi to a fixed value (somewhere between atan(1) and atan(10)) doesn't change the graph significantly, at least not such that it turns the hockeystick upside down.

So this gives rho0/rho. This means that with (a constant) rho0, then rho as a function of w etc.. will be:

Sort of what you found.

Success!

Luc

Jan 12, 2019
01:51 PM

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Jan 12, 2019
01:51 PM

I would like to thank you for helping me double checking the calculation.

Today I finished the calculation using matlab. The result is the same with mathcad.

So I can pretty much be sure about the integration and my mathcad installation.

Rho0 = 2.44 uOhm.cm for Gold. This is a bulk resistivity.

I got from this.

https://aip.scitation.org/doi/10.1063/1.1473868

It's a bad article because it doesn't specify what phi is, and if phi is really atan(w/h)

Yes, I am also confuse. but from the original paper, where the formula comes from, it is said it is "the azimuthal around z axis". I am not sure if I am able to derive the formula from its general form, so I cannot guarantee whether they refer to the same angle. z axis is **parallel **with cross sectional area **vector A**.

https://royalsocietypublishing.org/doi/pdf/10.1098/rspa.1950.0107

For values of w<43 nm Mathcad (11) cannot find a converging solution (TOL=10^-7). And you see I did use phi=atan(w/h).

I guess, the formula is valid for w/h>1.xx.

This is my matlab result.

Thank you once again for your help.