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Is there a way : 1i^(-2i), symbolic, ==> e^Pi ?

lvl107
20-Turquoise

Is there a way : 1i^(-2i), symbolic, ==> e^Pi ?

   Hello, Everyone.

   From :

(1).PNG

      Is there a way : 1i^(-2i), symbolic, ==> e^Pi  ?

           Thanks in advance.

1 ACCEPTED SOLUTION

Accepted Solutions
-MFra-
21-Topaz II
(To:lvl107)

1 REPLY 1
-MFra-
21-Topaz II
(To:lvl107)

....Only so:

onlyso.jpg

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