Greg,
My understanding of your problem is:
For a given total area "AT" determine the "h" that gives that value of AT
Simple solution is to use a solve block not the programming ability of Mathcad.
Step 1:
Make any equation for a variable with "h" on the left hand side a function with "h" as a parameter.
If you subsequently use in right hand side of new equations any redined variables that are now functions, this has also got to be a function in"h"
Step 2
Now you have a problem with a final equation for AT that is a function of h
Before the solve block you guess a value of what your are trying to find - in this case h
Type "Given" to start the solve block. You only need one equation in the solve block as you only have one guess variable h
This equation is AT(h) = 5 in2. You use the equality equals in a solve block.
Then you use the "Find" statement to get the appropriate value of "h".
Comment
This is a powerful and simple method of iterating even very large problems to a solution. You are not limited to one variable. In the solve block you can have many equations in many variables. You can also use the Minimize and Maximize instead of Find to optimise. the algorithm used to find the solution can obtain different results based on the functions and the start guess values used. It solves for solution nearest the guess value.
Answer.
Have done this for your problem to show you.
Disable the range variable for h and set it as a guess value
Changed variable names into function in h. Working from top to bottom until the AT(h) is made
Used AT(h) = 5 in2 to get right h value.
Hope understanding of what you are after and demonstration is Ok
Yes I will freelance on this stuff. terryhendicott_at_ymail_dot_com Have used MathCad since MathCad 6 a long time ago.
Cheers - Merry Mathcadding.
) Tezza2010 showed you the best way to do this though (using a solve block).
