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Question about arg() function

Ilyaa1ien
1-Newbie

Question about arg() function

How do I make so that was the result of the less -pi.

It is necessary for me to build a graph so as I need on this graph show that the function goes to -270 degrees but as soon as mathcad function comes to - 180 degrees mathcad makes leap up and continued to build the graph in the range from pi to 0. here is a screenshot how it looks

http://img152.imageshack.us/img152/3601/mathj.jpg

7 REPLIES 7
MikeArmstrong
5-Regular Member
(To:Ilyaa1ien)

Any chance of providing a worksheet?

Mike

In Attach

RichardJ
19-Tanzanite
(To:Ilyaa1ien)

You could use the angle function instead of the arg function. This is defined over 0 to 2*pi. If the phase goes outside of that range then you need to calculate a vector pf phase values, and then unwrap it.

I got some errors

http://img221.imageshack.us/img221/4990/65783339.jpg

RichardJ
19-Tanzanite
(To:Ilyaa1ien)

Which version of Mathcad are you using?

Mathcad, version 14.0.0

RichardJ
19-Tanzanite
(To:Ilyaa1ien)

You should download and install M020 (if you are a single user) or M030 (if you have active maintenance; do not install M035!).

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