Recurrence Relations

[ptc-4341824]

Okay guys, more to think about.

each of the following recurrence relations has the property that if a sequence generated by the recurrence relation converges to a limit in the interval (0,16/9), then that limit must be a solution of f(x) = 36

A:

x = 72(2-x)^2

n+1 (16-9x )(20-9x ) (n = 0,1,2......)

n n

B:

x = 2 (11-Square root 72 - 31 )

n+1 9 x (n = 0,1,2......)

n

Generate the sequence starting with x = 1.7 for each recurrence relation and tabulate the results to six decimal places

0

Show seperately the solution to f(x) = 36 to six decimal places

I know you experts like a challenge.....lol

Paul

[ValeryOchkov]

May be this

http://twt.mpei.ac.ru/ochkov/Sovet_MC/238/238_Round_Error.gif

will helpfull to you

[ptc-4341824]

Just to be clear,

The equations contain 9x subscript n

And its square root of 72/x subscript n

Finally, the generation of the sequence is x subscript 0

Must learn how to type these equations in word....lol

[RichardJ]

Could you please put this into a mathcad worksheet, and post it.

[ptc-4341824]

On a mathcad spreadsheet as requested.

[RichardJ]

Set up a range variable to index a vector, x. Then the recurrence relation will fill the vector, and you can look at the results.

[ptc-4341824]

Can anyone add anymore?

[RichardJ]

It looks to me like some sort of homework assignment. In such cases the general rule around here is that you get help, but we don't do it for you. Post a workksheet showing your attempt to get beyond what I did.