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Hello,
I have separated a small for-loop from my calculation. This also works correctly.
Now I would like to save ai for each i or rather access individual values. Furthermore, I would like to draw a graph. y-->ai and x-->i
I would be grateful for any help 🙂
Kind regards
Max
Solved! Go to Solution.
@MS_12003747 wrote:
Hello,
I have separated a small for-loop from my calculation. This also works correctly.
Now I would like to save ai for each i or rather access individual values. Furthermore, I would like to draw a graph. y-->ai and x-->i
Hi, Max.
A solution to the requirement is to add each ai value to a vector in the loop and then return the whole vector. I've added 'comments' to each line that I've modified - note that the return in the last line is necessary, otherwise, Mathcad returns the vector and the comment.
Then simply create a range variable to match the new vector and plot the result.
Stuart
Edited to add:
I've had an unreliable internet service today and couldn't upload your (modified) worksheet. However, as the output of the calculation looks almost linear, I guessed that increasing the ai interval by 100 or so, shouldn't have too much effect on the results; it doesn't appear to, only differing by 0.01 from the original value.
This allowed me to reduce the size of the worksheet from almost 5 MiB to 294 KiB, which should be (and was) sufficiently short to reliabily upload.
@MS_12003747 wrote:
Hello,
I have separated a small for-loop from my calculation. This also works correctly.
Now I would like to save ai for each i or rather access individual values. Furthermore, I would like to draw a graph. y-->ai and x-->i
Hi, Max.
A solution to the requirement is to add each ai value to a vector in the loop and then return the whole vector. I've added 'comments' to each line that I've modified - note that the return in the last line is necessary, otherwise, Mathcad returns the vector and the comment.
Then simply create a range variable to match the new vector and plot the result.
Stuart
Edited to add:
I've had an unreliable internet service today and couldn't upload your (modified) worksheet. However, as the output of the calculation looks almost linear, I guessed that increasing the ai interval by 100 or so, shouldn't have too much effect on the results; it doesn't appear to, only differing by 0.01 from the original value.
This allowed me to reduce the size of the worksheet from almost 5 MiB to 294 KiB, which should be (and was) sufficiently short to reliabily upload.
Really, thank you very much! I now understand the procedure! This helps me a lot!
Kein Problem, Max.
Stuart
I have just one more question.
Is it also possible to simply save a vector, e.g. for DeltaK from the loop ? The variable is not known outside of the loop.
The loop only gives me a vector for ad.
Thanks and best regards,
Max
Sorry,
it was just possible using a matrix!
Thanks anyway!
Auch kein Problem, Max. (na ja, jedenfalls nicht für mich!)
Freut mich, dass du das geklärt hast
Stuart