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Nov 15, 2019
04:45 PM

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1 ACCEPTED SOLUTION

Accepted Solutions

Nov 24, 2019
04:48 PM

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Nov 24, 2019
04:48 PM

15 REPLIES 15

Nov 15, 2019
05:46 PM

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Nov 15, 2019
05:46 PM

You should NOT use global assignments ( __=__ ), but boolean equality to define the equations in your solve block. Type [CTRL =] to get those. They show as a **bold** equals sign ( **=** ).

Success!

Luc

Nov 15, 2019
07:09 PM

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Nov 15, 2019
07:09 PM

- Tags:
- Mathcad Usage

Nov 15, 2019
07:36 PM

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Nov 15, 2019
07:36 PM

Additional remarks:

1) You have to only use the function names without the argument parenthesis (use "C" and not "C(t)")

2) You have only 5 equations but 6 functions to solve for.

Nov 24, 2019
02:59 PM

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Nov 24, 2019
02:59 PM

I attached new pic.

can you solve it please..

Nov 16, 2019
11:00 AM

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Nov 16, 2019
12:54 PM

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Nov 16, 2019
12:54 PM

Thank you, can you attached file please?

Nov 16, 2019
01:00 PM

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Nov 16, 2019
01:00 PM

and why is f(t):0.5*cosh(t)??

Nov 16, 2019
02:21 PM

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Nov 16, 2019
02:21 PM

Hi,

you should provide the f (t); what I chose is a convenience function. I do not believe that Mathcad is able to determine f (t) as an unknown knowing only its initial condition.

Nov 16, 2019
02:39 PM

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Nov 16, 2019
02:39 PM

thank you

but the answer is below the attached file.

Do you know why?

please..

Nov 18, 2019
05:36 AM

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Nov 18, 2019
05:36 AM

Hi,

If there were a further differential equation in f(t), things would change. See the following example:

Nov 24, 2019
11:02 PM

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Nov 24, 2019
11:02 PM

can you send me a file?

Nov 26, 2019
11:33 AM

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Nov 18, 2019
01:50 PM

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Nov 18, 2019
01:50 PM

That very blurry picture shows a graph with only 4 traces. That's 4 functions, not 6.

Are you sure you have entered the complete set of ODE's, required for solving the 6 functions that you are trying to find?

Luc

Nov 24, 2019
02:58 PM

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Nov 24, 2019
04:48 PM

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Nov 24, 2019
04:48 PM

Story continues here: https://community.ptc.com/t5/PTC-Mathcad/too-many-initial-conditions/m-p/637903#M188074