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sin(x) / { x - 2*pi*floor[(pi + x)/(2*pi)] } solve, x, fully ?

lvl107
20-Turquoise

sin(x) / { x - 2*pi*floor[(pi + x)/(2*pi)] } solve, x, fully ?

Hello Everyone.

From :

I.PNG

sin(x) / { x - 2*pi*floor[(pi + x)/(2*pi)] } solve, x, fully ?

Thanks in advance.

Regards.

Loi.

5 REPLIES 5

Hi,

 

Of the last 31 posted questions 17 have been from lvl107.  Over a half.

Is this considered a monopolisation of the thread?

 

Cheers

Terry


@terryhendicott wrote:

 

 

Is this considered a monopolisation of the thread?

 Cheers

Terry


I don't think the intent is to monopolize; I believe lvl107 is enjoying seeing people discuss basically the same techniques over and over and over . . .

 

I do believe what is being observed is a reduction of questions and problems posted as users abandon Prime (and Mathcad) in response to 

  • The reduced usability of Prime, and
  • The new billing scheme of an annual fee (i e, renting your software) 

I'm afraid Fred's assessment is correct.

 

But I also fear that lvl107's mindless exercises are a "turn-off" for people who prefer to see mathcad worksheets as effective tools for serious technical work.

lvl107
20-Turquoise
(To:lvl107)

Oh..., I propose one of solutions :

 

II-.PNG 

Best Regards.

Loi.

Fred_Kohlhepp
23-Emerald I
(To:lvl107)

What purpose?

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