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8-Gravel

## this variable is undefined

11 REPLIES 11
23-Emerald I
(To:JPark61)

You've not learned that all of the constraints have to come after the "given" statement?  Where is "Find"?

Go read the help files about how to set up a solve block!

Or are you just dumping on this forum?

how can i solve range problem.

21-Topaz II
(To:JPark61)

8-Gravel
(To:-MFra-)

i have a question so only i want to find d.1 d.2.

all variables are a constant value.

so do I have to change d.a=0.1 not :=

21-Topaz II
(To:JPark61)

Hi,

the Ks are all uppercase or lowercase.....

8-Gravel
(To:-MFra-)

Thank you!!

can you send me a file??

why my computer does not work

21-Topaz II
(To:JPark61)

8-Gravel
(To:-MFra-)

thank you

but why d.a d.b is not corret it should be 0.1 and 0.1

24-Ruby V
(To:JPark61)

If ALL of your used variables have to be constant (even q=100) and you only want to vary d1 and d2m then you are asking for the impossible. There is a linear relationship between d1 and d2 and to fulfill your equation at least one of the two must be negative. So they can't be both in the range from 0 to 0.3.

8-Gravel
(To:Werner_E)

q is not constant value.

24-Ruby V
(To:JPark61)

@JPark61 wrote:

q is not constant value.

This is exactly what MFra already had shown quite a while ago.

If q is variable, too, you have a myriad number of solutions. And if you chose a q value for which a solution exists, there usually exist an infinite number of additional solution for d1 and d2.

So you have some additional degrees of freedom.

Some exemple:

q=10, d1=0.1, d2=0.121

or

q=10, d1=0.15, d2=0.071

or

q=10, d1=0.2, d2=0,021

etc.

Here is the formula where you can calculate d2 if q and d1 are given:

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