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Community Tip - When posting, your subject should be specific and summarize your question. Here are some additional tips on asking a great question. X

two eq. with two unknows.

kenan2
12-Amethyst

two eq. with two unknows.

Hello.

How can I solve for c_1 og c_2 symbolic?

 

1 ACCEPTED SOLUTION

Accepted Solutions
LucMeekes
23-Emerald III
(To:kenan2)

Create a 2 element vector and put in the equations. It's simple.

 

Success!
Luc

View solution in original post

6 REPLIES 6
Fred_Kohlhepp
23-Emerald I
(To:kenan2)

Well, first you must assume that c3 is constant. . . 

LucMeekes
23-Emerald III
(To:kenan2)

I think that Prime cannot solve a solve block symbolically.

But if you write it simply like this:

LucMeekes_0-1583930741370.png

You get your answer, for c1 and c2 in terms of the other items in the equations.

Note that u3 is common to both equations, so your problem can also be described with:

LucMeekes_0-1583930960385.png

This gives you a free choice for c1, then with u1, u2, c3 and l known, you can calculate c2.

 

Success
Luc


@LucMeekes wrote:

I think that Prime cannot solve a solve block symbolically.

 


That's correct. It would be possible to do so in real Mathcad (=Mathcad 15 and below) but they destroyed this possibility when they developed Prime. So the only way is to use the symbolic "solve" command as you had shown.

 

kenan2
12-Amethyst
(To:LucMeekes)

I don't understand, how do you put it like that, in a matrix or what?

Can you maybe send the mathcad file..

LucMeekes
23-Emerald III
(To:kenan2)

Create a 2 element vector and put in the equations. It's simple.

 

Success!
Luc

LucMeekes
23-Emerald III
(To:kenan2)

There's more wrong with your sheet.

You define two equations with c1, c2, u1, u2 etc. these symbols are all labelled as constants.

Then you write the Find function where you want to solve c1 and c2, but these are labeled as <nothing>.

NOTE that a constant c1 is very different from a variable c1, or a unit c1 (if that would be defined).

Written like this, Prime can never solve it.

 

Success!
Luc

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