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Sweep ?

AndyHermanson
12-Amethyst

Sweep ?

I have a user that wants to have a variable section sweep that creates a “cup” geometry to mimic what is seen on LEDs. However in Creo I can’t get the section to be perpendicular to the axis and trajectory. See below. I want a cup like what is shown in the blue lines, but all I can seem to get is interference in the corners as shown with the red lines. He can do a rotated cup, but that wont include the corners of the square in the “cup”. Any ideas for us?

 

sweep.png


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5 REPLIES 5

You are on the right track but you need to lock the center point in the sketch.

Have a look at this thread: Create hex/pentagon shaped dimples on a circular surface.

If you scroll further to the bottom you will find an included PRT file (Creo 2.0 full version) of the honeycomb sweep.

Yours should be fairly straight forward to do what you need it to do.

You know, i always say its simple and it rarely is

Indeed, there are a few tricks you must be aware of when using sweep.

In this case, the Sweep acts normal to the trajectory. In order to make the sweep revolve around the axis, you need a circular trajectory (Origin). The periphery is a "guide chain" (Chain 1; rule bases tangent). Further more, the endpoint of Chain 1 needs to be in line with the endpoint of the trajectory circle (Origin). If you divide the midpoint of the line in the Extrude sketch, you will have an endpoint there to align with the circle. Orienting the sketch for the circle will also let the circle align properly (without adding an additional Divide).

For the sweep sketch, note that you don't even have to touch the selected Origin. Inn the example attached, the arc is attached to the edge and to the axis reference.

So what happens now is that the circle defines the normal direction, but the section sketch follows its references.

Hope all that makes sense.

shrinkage_sink.PNG

The attached file is Creo 2.0 full version.

What Tom said.

I'd add, this is not a Creo limitation, it's a geometry limitation. You cannot define a plane through the axis and normal to the outer edge at any point along that edge. A plane with those constraints only exists at six discreet points, one for each segment of the perimeter. The circle allows the plane to be normal at any point around the axis.

--
Doug Schaefer | Experienced Mechanical Design Engineer
LinkedIn

Thanks a bunch guys. You guys are a great help. Damian and Ron over on the exploders came up with the solution we went with though.

http://portal.ptcuser.org/p/fo/st/thread=41018

Video:

http://www.youtube.com/watch?v=upBZkdF9n3w&feature=c4-overview&list=UU89vS9l-hjWue8YteZ56esA

Also a great solution. Thanks for sharing that, Andrew.

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