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A question about a geometric series

yhuang-3
1-Visitor

A question about a geometric series

Hi All, I am trying to solve a geometric problem.


A typical geometric series can be written like this, where N and M are two commensurable constants, i is the imaginary unit. 

geometric.JPG

For this kind of geometric series, it can be derived by hand that it is equal to

geometric2.JPG


If we are trying to solve this expression, by introducing a (k-1) as a coefficient of the exponential function, how can we solve it?

geometric3.JPG


It is not necessarily to be done by Mathcad. Thank you!



ACCEPTED SOLUTION

Accepted Solutions
Werner_E
25-Diamond I
(To:yhuang-3)

Simplify means just that. Its NOT an approximation, its an exact equivalent. So the answer to your question 1 is clearly YES.

Mathacds symbolics is sometimes quite tricky and its often hard to impossible to find out what keywords in what order to use to get the result in the way we expect it.

You see by my examples that the way Mathcad displays its result differs depending on how we tell Mathcad what to do.

I was surprised to see the much more compact result when I gave Mathcad the expression in q and then told it to substitute for the quotient of your example.

But Mathcad and especially its symbolic is always good for a surprise.

Symbolics is not the strongest part of Mathcad and so you may consider using Maple or Mathematica instead for more complicated symbolic calculations.

Also the free online Wolfram Alpha might be an option:

View solution in original post

8 REPLIES 8
Werner_E
25-Diamond I
(To:yhuang-3)

> If we are trying to solve this expression,

"solve" ???

I see no equations which could be solved (for which variable?).


I guess you know that your last expression is NOT a geometric series.

Sorry, I did not mention it correctly. I want to know how to  simplify this expressiongeometric3.JPG, by removing the Sigma symbol and write it as an expression whose manner is similar to geometric2.JPG

This is more like a mathematical question, but not Mathcad question.

Thank you!

Werner_E
25-Diamond I
(To:yhuang-3)

> This is more like a mathematical question, but not Mathcad question.

But you can use Mathcad to do the job 😉

Something like this:

Hi  Werner Exinger, thank you so much for your advise.   I have one question about the function of "simplify" here in your first pircture:

GEOMETRY 4.png

For the first simplify process, we know the result is the exact equivalent expression, not a "simplified" one.

My questions are :

(1) is the result in the second raw also the exact expression, instead of a "simplified" one?

(2) from the 2nd picture you posted, it seems like the answer of the question 1 is NO. Then would you tell me what kind of simplification Mathcad did?

(3) if the answer of the question 1 is YES, then that is what exactly I am looking for. Would you tell me the name of this kind of expression, then I can look for the references to derive the expression from the Left Hand Side of the "simplify" operation to the Right Hand Side?

Thank you!

Werner_E
25-Diamond I
(To:yhuang-3)

Simplify means just that. Its NOT an approximation, its an exact equivalent. So the answer to your question 1 is clearly YES.

Mathacds symbolics is sometimes quite tricky and its often hard to impossible to find out what keywords in what order to use to get the result in the way we expect it.

You see by my examples that the way Mathcad displays its result differs depending on how we tell Mathcad what to do.

I was surprised to see the much more compact result when I gave Mathcad the expression in q and then told it to substitute for the quotient of your example.

But Mathcad and especially its symbolic is always good for a surprise.

Symbolics is not the strongest part of Mathcad and so you may consider using Maple or Mathematica instead for more complicated symbolic calculations.

Also the free online Wolfram Alpha might be an option:

Werner_E
25-Diamond I
(To:yhuang-3)

Here is a different approach which displays the result in a different manner

Werner_E
25-Diamond I
(To:yhuang-3)

Concerning the name of the series k*q^k.

I guess there is no special name. its just a variant of the geometric series.

You sure will find a lot of links where it is shown how to derive the closed formula for it

Power Sum -- from Wolfram MathWorld

https://de.wikipedia.org/wiki/Geometrische_Reihe#Herleitung_der_Varianten

Forum "Folgen und Reihen" - k*q^k partielle summation - MatheRaum - Offene Informations- und Vorhilfegemeinschaft

Thank you Werner Exinger, you helped me so much!

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