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I am having an issue with finding the max value of positive and negative values. I want it to always pick the highest integer but to have it's sign remain the same.
For instance,
x=10, y=15, z=-20 are my numbers calculated that
t:=550*[max(x,y,z)] -p is depended on.
if I do r:= max(x,y,z) it will state that r=15 when I need it to pick the worse case for an equation it will be integrated in later on.
if I do r:= max(IxI,IyI,IzI) it will state r=20 but not -20 cause of the absolute value.
Is there a different approach I can do where I wouldn't have to use solve for t for each single case and pick the max absolute value of all three?
Solved! Go to Solution.
max(|x|,|y|,|z|)=max(x,y,z)
This is fallible but works most of the time
if test is true you have a positive number
if test is false you have a negative number
Hi Luc. I guess that your solution is correct, just a margin note: If x = max(A) then -x = min(-A).
Best regards.
Alvaro.
Here are my 2 cents
When I do that, it tells me that "these values must all be of one type."
I am not sure what that means.
Actually I was able to make it work with your method, Luc. thank you. My issue was that I was mixing {2,1} variables with {1,1} when what I needed to do first is find the maxabs of the {2,1} and then combine them all in one matrix to find the total maxabs of (B). It's a bit longer the steps but it gives the correct solution.