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## Equation for logarithmic linear equation  11-Garnet

## Equation for logarithmic linear equation

Hi

Need some help to create an equation for the 6 cases of  linear graph I attached the mathcad prime for your reference.

I cannot make the graph straight using  this formula ( y= mx+b)  because x  should be   in  logarithmic  distance Physical Mathematics

1 ACCEPTED SOLUTION

Accepted Solutions  18-Opal
(To:ldante)

ldante,

The equation is y=m*log(x)+b

For x1 & y1, this can be found to be y1=-0.52532*log(x1)+3.17596.

6 REPLIES 6  23-Emerald II
(To:ldante)

Hi Lex,

It's not completely clear what you want...

What you have is y=m*log(x)+b.

If you solve m and b in:   y1=m*x1+b

you get m=-0.01974 and b=3.21776.

You can do the same for the other sets.

Does this help?
Success!
Luc  18-Opal
(To:LucMeekes)

I think OP is looking for your equation y=m*log(x)+b.

If you solve for m & b in  y1=m*log(x1)+b

you get m=-0.52532 and b=3.17596  11-Garnet
(To:MJG)

Yes .. I need an equation . I am using  logarithmic scaling in x axis  .  Thank you in advance  🙂  18-Opal
(To:ldante)

ldante,

The equation is y=m*log(x)+b

For x1 & y1, this can be found to be y1=-0.52532*log(x1)+3.17596.  11-Garnet
(To:MJG)

Got it thanks   23-Emerald II
(To:MJG)

Guess you're right. Forgot to type the log().

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