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Hello,
i want to calculate following filter in series:
LC+RC+LC
spice simulation result:
with following transfer functions:
filter1:
filter2:
filter3:
Could i multiply all three transfer functions in laplace?
As result i get a different magnitude like in spice simulation. Could it be that transfer function of all in series shall calculate in a different way?
Second Question: How can i display the phase without overdue of 180° in the diagram?
Thanks in advance.
Michel
Hi Michel,
You can't simply multiply the three transfer functions. Doing so, you obtain a transfer function that isn't the one corresponding to three cascaded filters
Insted to obtain a transfer function that is the one corresponding to three cascade filters, you must place a buffer between each filter.
In other words, see the bloch diagram:
Results for R=21.3mOhm
Results assuming R=213m_Ohm:
A few initial points:
I would normally use a nodal analysis and solve for the various circuit currents using matrices (which is what Mathcad is good at). Here is a useful link to this technique: https://en.wikiversity.org/wiki/Electric_Circuit_Analysis/Mesh_Analysis
Assuming that the T0200 device shown in your first circuit diagram is a 213 mOhm resistor (you indicate that the middle part of the filter is an RC section), the graphs you provide of the simulation do not match with the behaviour of the circuit. The phase characteristic you have is showing an increase in phase shift from about 12 kHz to 120 kHz. With the circuit as shown the phase only decreases.
In Mathcad the circuit can be analyzed with:
Then:
And we can set:
Which gives:
From which the transfer characteristic is found with:
giving:
Now we can plot:
Success!
Luc