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How to sum ​​up the results?

jkowalski
12-Amethyst

How to sum ​​up the results?

hi . . my name is Jan

i know very litle about programing. still learning from tutorials. u can call me a beginner.

now i need to sum results

Could anyone help, please.

The attached file is an explanation of everything.

I'm using Mathcad 15.

ACCEPTED SOLUTION

Accepted Solutions
Werner_E
25-Diamond I
(To:jkowalski)

1) You did not cycle from 0..N but simply calculated W for N=2. That way W only gets the value for N=2 ((18))

Solution: Write a prog which cycles from 0 to N calculates the values and append them to the vector W

2) Even then you could not use the sum symbol you tried as this only sums up vectors consisting of numbers. What your calculation of W produces is a nested vector.

Solution: change all calls to "pick(......)" to "pick(.....)[0" and you get a vector of the numbers you want which you can sum as you had tried.

comment: I think whatever you sheet should do could possibly be done less complicated. At least on first sight it looks like the combinaton of "match" and "pick" could be replaced by a simple use "lookup" - but then I may be wrong, so give it a try..

helpsum1.png

View solution in original post

11 REPLIES 11

I didn't try to figure out what your program is doing, but you are on the right track. The variable W is a single value = 18, and if you sum that, you get 18.

It looks to me as if W will only return a single value.

~R~

Werner_E
25-Diamond I
(To:jkowalski)

1) You did not cycle from 0..N but simply calculated W for N=2. That way W only gets the value for N=2 ((18))

Solution: Write a prog which cycles from 0 to N calculates the values and append them to the vector W

2) Even then you could not use the sum symbol you tried as this only sums up vectors consisting of numbers. What your calculation of W produces is a nested vector.

Solution: change all calls to "pick(......)" to "pick(.....)[0" and you get a vector of the numbers you want which you can sum as you had tried.

comment: I think whatever you sheet should do could possibly be done less complicated. At least on first sight it looks like the combinaton of "match" and "pick" could be replaced by a simple use "lookup" - but then I may be wrong, so give it a try..

helpsum1.png

jkowalski
12-Amethyst
(To:Werner_E)

Wow!!

Thank you very much Werner

See what i can to do make it even simpler.

Thanks for the replay.

Werner_E
25-Diamond I
(To:jkowalski)

You are welcome!

I'm simplified the function.

Werner_E
25-Diamond I
(To:jkowalski)

Jan Kowalski schrieb:

I'm simplified the function.

Fine. Whats comes to my mind now is the following: You could put the numbers you are looking for in a vector and use a for loop in which you use lookup to create another vector with either the correspunding values in K<1> or 0 if not found. This vector is then multipied by a vector consisting of the values (250000, 10000, 520, ...) to get the result for the Vector W_. Not necessarily shorter but probably easier to maintain.

jkowalski
12-Amethyst
(To:Werner_E)

Wow thanks your mind is amazing.


i'm looking for even the relationship between the vectors see atached file.

Werner_E
25-Diamond I
(To:jkowalski)

i'm looking for even the relationship between the vectors see atached file.

Hmm - your K0, K1 and K2 are not vectors but matrices. You can add matrices only if all are of the same dimension, that is, all have the same number of rows AND the same number columns. This does not work here as K0 has 4 rows while the other two matrices have only 3 rows. I am not sure what kind of addition you are heading for.

As I understand you want Mathcad to do the following addition:

04.01.png

I have no clue what kind of addition this should be. As already stated you can not add matrices with different dimensions. Even if I fill the necessary space with zeros, the result would differ quite a lot from what you want to achieve.

04.01_2.png

So what Math do you apply to arrive at your solution 5x2-matrix?

Werner_E
25-Diamond I
(To:jkowalski)

I think I realized what you mean. I have the feeling that it could be done much shorter and more elegant, but I can't think of a better way in the moment.

04.01_3.png

jkowalski
12-Amethyst
(To:Werner_E)

hey.

Thanks for reply.

Ok.I thought a little different,but you were able to do what I thought.

Sorry my english is poor (Google translator)

Werner_E
25-Diamond I
(To:jkowalski)

Jan Kowalski schrieb:

hey.

Thanks for reply.

Ok.I thought a little different,but you were able to do what I thought.

Sorry my english is poor (Google translator)

Glad I could help.

No need to apologize for your English. It's not my primary language either and I too have my difficulties with.

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