Integral Calculation

[SriramVS]

Guys,

I have a integral caluclation to be done to calculate the profile of a tyre. I need to vary two variables namely r and alpha and need to get a graph out finally.

I tried varying "r" alone , and the equation was working perfect. But woth two variabkes varying in tandem , MathCAD isn;t able to calculate the result.

The calculation sheet is attached herewith.

[TKHunny]

Why would you expect a surface plot to appear on a 2D chart.

Change your definition to d(a,r):=Im(Your Integral)

Press [Ctrl]-2 (Or get a surface plot up some other way.)

Put 'd' in the place holder of the Surface Plot..

Double click the plot and Under [QuickPlotDate] change Range 1 to [43,45] and Range 2 to [209,312].

Of course you may need to change your screen resolution to 16 Bit High Color before loading the Surface Plot. (Very irritating)

[SriramVS]

Nathan ,

No I need a 2D plot with the equation result varying with "r" . But to ge the equation result , i have 2 sets of data for "Alpha" and "r" respectively whcih I need to substitute in the equation.

[RichardJ]

Do you mean this?

[SriramVS]

Thanks , I got the solution. But I need a small tweaking here . I need the equation to pick up the "alpha" and "r" from a table (which is what i wrote as a matrix) and give the correspondign "d" value. then the graph needs to be drawn with "d" and "r" . I'm attaching the table for your reference

[RichardJ]

I need the equation to pick up the "alpha" and "r" from a table (which is what i wrote as a matrix) and give the correspondign "d" value.

That's what it does now.

the graph needs to be drawn with "d" and "r"

The graph plots d against r

[Fred_Kohlhepp]

Just an observation:

You create alpha as {40,43,45} which (I assume) are angles in degrees.

But whe you specify sin(alpha) Mathcad will take these as 40 radians and you will get the sine of 40 radians.

[RichardJ]

Good catch

Although the angle appears to make little difference anyway!

[Fred_Kohlhepp]

Although the angle appears to make little difference anyway!

Spent some time trying to show that the angle fell out of the integral and didn't matter at all; had to stop--work keeps interrupting!

[TKHunny]

I hope not, since that's what I did with a fairly simple rotation.

I guess if you have specific requirements, a generalization is not necessarily welcome.