Hello, Everyone.
Thanks in advance for your time and help.
Best Regards.
You sure can't multiply a 3x3 by a 4x4 matrix! To obtain a 3x4 matrix you have to multiply a 3 x n matrix with a n x 4 matrix.
Why don't you simply use normal matrix arithmetic to get the "factorization" you need - if you need the result at all. You have different ways to do so:
And a similar query :
Thanks in advance for your time and help.
Best Regards.
Why do you want to solve for 21 variables when you only have 12 equations???????????????
The way to do it is exactly the same as I have shown above (2nd), just do it symbolically. the 3x3 matrix can be anything as long as the matrix isn't singular.
I greatly appreciate your time and help to my questions, Werner. And I have a different question and I have observed the following :
I need help with the reason : the equation, the above ( red one ) , was not solved for 14th unknown ( X[13 ) .
Thanks again.
Best Regards.
I need help with the reason : the equation, the above ( red one ) , was not solved for 14th unknown ( X[13 ) .
As already described above - you only have 12 equations but 14 variables to solve for. Mathcads solve does not like over or undedetermined systems.
Werner,
It seems that " no solve for 14th unknown X[13 " :
Thanks again.
Best Regards.
Yes, Mathcad's symbolics could find a/the solution in this case, but it doesn't. Seems its not perfect 😉