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19-Tanzanite

## Matrix Factorization.

Hello, Everyone.

Best Regards.

8 REPLIES 8
24-Ruby V
(To:lvl107)

You sure can't multiply a 3x3 by a 4x4 matrix! To obtain a 3x4 matrix you have to multiply a 3 x n matrix with a n x 4 matrix.

24-Ruby V
(To:lvl107)

Why don't you simply use normal matrix arithmetic to get the "factorization" you need - if you need the result at all. You have different ways to do so:

19-Tanzanite
(To:lvl107)

And a similar query :

Best Regards.

24-Ruby V
(To:lvl107)

Why do you want to solve for 21 variables when you only have 12 equations???????????????

The way to do it is exactly the same as I have shown above (2nd), just do it symbolically. the 3x3 matrix can be anything as long as the matrix isn't singular.

19-Tanzanite
(To:Werner_E)

I greatly appreciate your time and help to my questions, Werner. And I have a different question and I have observed the following :

I need help with the reason : the equation, the above ( red one ) , was not solved for 14th unknown ( X[13 ) .

Thanks again.

Best Regards.

24-Ruby V
(To:lvl107)
 I need help with the reason : the equation, the above ( red one ) , was not solved for 14th unknown ( X[13 ) .

As already described above - you only have 12 equations but 14 variables to solve for. Mathcads solve does not like over or undedetermined systems.

19-Tanzanite
(To:Werner_E)

Werner,

It seems that " no solve for 14th unknown X[13 " :

Thanks again.

Best Regards.

24-Ruby V
(To:lvl107)

Yes, Mathcad's symbolics could find a/the solution in this case, but it doesn't. Seems its not perfect 😉

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