Community Tip - Your Friends List is a way to easily have access to the community members that you interact with the most! X
J and Big Omega are 3x3 matrices. Little omega is a 3x1. Mathcad will not solve this with the matrices defined and gets the wrong answer with them undefined. Nu should be equal to (Omega)*J*(Little Omega). Any idea why this is happening?
(Mathcad Prime 9.0)
@LA_10815809 wrote:
J and Big Omega are 3x3 matrices. Little omega is a 3x1. Mathcad will not solve this with the matrices defined and gets the wrong answer with them undefined. Nu should be equal to (Omega)*J*(Little Omega). Any idea why this is happening?
Yes.
The symbolics unfortunately is not made for solving for vectors and matrices.
In the first two symbolic expressions your pic shows all used variables are treated and interpreted as scalars. J^-1 is seen as 1/J, not as the inverse of a matrix. The symbolic can't know that vectors and matrices are meant!
The result obtained just happens to be correct for matrices and vectors as well.
You can't rely on the results if you have matrices and vectors in mind instead of scalars!!
For example:
The given result is wrong twice if J and Omega are 3x3 matrices and omega is a 3x1 vector.
First the order of the result is wrong as we can't multiply a 3x1 vector with a 3x3 matrix, omega would have to be placed at the end to be the last factor.
And second we can't simplify J*Omega*J to Omega*J^2 because matrix multiplication is not commutative.
So its just by chance that the result given for your equation happens to be correct for the matrices as well.
In your last expression the same applies, but just concerning eta. eta is seen as a scalar variable and therefore Primes symbolics throws the error about not matching array dimensions -> if eta would be a scalar, the first summand would be a 3x3 matrix but the second a 3x1 matrix/vector.
Here, a "more intelligent" symbolic engine could well conclude on its own that eta must be a 3x1 vector and give the corresponding solution.
But Prime needs the user's help here by clearly specifying a corresponding vector instead of eta.
And because Primes symbolics always outputs the result in rows when solving for several variables, you also have to transpose the result yourself 😞
You could also use a numeric solve block instead of the symbolic "solve". Here you must provide a guess value for eta and so its of course also clear that a 3x1 vector is meant: